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Question

If a straight line passing through the point $$P(-3, 4)$$ is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is:


A
xy+7=0
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B
3x4y+25=0
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C
4x+3y=0
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D
4x3y+24=0
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Solution

The correct option is D $$4x - 3y + 24 = 0$$
Let the line be $$\dfrac{x}{a} + \dfrac{y}{b} = 1$$

$$(-3, 4) = \left [ \dfrac{a}{2} , \dfrac{b}{2} \right]$$

$$a = -6, b = 8 $$

equation of line is $$4x - 3y + 24 = 0$$

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