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Standard XII

Chemistry

Rate of Reaction

The concentra...

Question

The concentration of a reactant changes from .03M to .02M in 25 minutes. The average rate of reaction, using time in seconds is

0.4 \times 10^{- 3} m o l / l / s

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0.024 m o l / l / s

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0.24 m o l / l / s

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6.67 \times 10^{- 6} m o l / l / s

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Solution

The correct option is D $6.67 \times 10^{- 6} m o l / l / s$
$R a t e = \frac{Δ [R]}{Δ t} = \frac{- (0.02 - 0.03)}{25 \times 60} = 6.67 \times 10^{- 6} m o l / l / s$

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Q. The concentration of a reactant changes from .03M to .02M in 25 minutes. The average rate of reaction, using time in seconds is

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The concentration of a reactant changes from .03M to .02M in 25 minutes. The average rate of reaction, using time in seconds is

The correct option is D 6.67×10−6mol/l/sRate=Δ[R]Δt=−(0.02−0.03)25×60=6.67×10−6mol/l/s

The correct option is D $6.67 \times 10^{- 6} m o l / l / s$
$R a t e = \frac{Δ [R]}{Δ t} = \frac{- (0.02 - 0.03)}{25 \times 60} = 6.67 \times 10^{- 6} m o l / l / s$