If $A^{T} B^{T} = C^{T}$ then C =

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ABC

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Solution

The correct option is B BA
By transpose properties
we know that
${(A B)}^{T} = B^{T} A^{T} a n d {(A^{T})}^{T} = A$
Given
$A^{T} B^{T} = C^{T}$
${(B A)}^{T} = C^{T}$
Take transpose of both side
${({(B A)}^{T})}^{T} = {(C^{T})}^{T}$
$B A = C$

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