CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a tower subtends angles θ, 2θ and 3θ at three points A,B and C respectively, lying on the same side of a horizontal line through the foot of the tower, ABBC is equal to?

A
sin2θsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
sin3θsin2θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
sin3θsinθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
cotθcot2θcot2θcot3θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C sin3θsinθ
Let PQ be the tower s given PAQ=θ
PBQ=2θ,PCQ=3θ
BPA=CPB=θPAB
PAB=BPA=θ
AB=BP -(1)
In PBC (By) sine rule
BPsin(18003θ)=BCsinθ
ABsin3θ=BCsinθ {form(1)}
ABBC=sin3θsinθ

354549_197066_ans_b6bb5b896c16422695e90877b0c3d7d0.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon