If a trapezium ABCD has parallel side AB and CD measured 13 and 17 cm what should be the area of trapezium if the area of triangle ABC = 71cm2.
163.5
According to the given information:
ar(ΔABC)=71 cm2 and B=13 cm
⟹12×13×H=71
⟹H=10.9m
As we know:
⟹ar(quad.ABCD)=AB+CD2×H
ar(quad.ABCD)=163.5 cm2