If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of area of the triangle to the area of parallelogram is :

1 : 3

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1 : 2

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3 : 1

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1 : 1

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Solution

The correct option is D 1 : 2

Area of Parallelogram $= (B a s e) (H e i g h t) = b h$

Area of triangle $= \frac{1}{2} (B a s e) (H e i g h t)$
$∴$ Ratio of Areas $= 1 : 2$

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Q. Question 9
If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of the parallelogram is:

A) 1:3
B) 1:2
C) 3:1
D) 1:4

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If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of area of the triangle to the area of parallelogram is :

The correct option is D 1 : 2Area of Parallelogram =(Base)(Height)=bh Area of triangle =12(Base)(Height)∴ Ratio of Areas=1:2

The correct option is D 1 : 2

Area of Parallelogram $= (B a s e) (H e i g h t) = b h$

Area of triangle $= \frac{1}{2} (B a s e) (H e i g h t)$
$∴$ Ratio of Areas $= 1 : 2$