{ If }a^{x-1}=bc,b^{x-1}=ca and }c^{x-1}=ab then }xy+yz+zx=}{ (a) }xyz

Open in App

Solution

Suggest Corrections

Similar questions

a^{x - 1} = b c, b^{y - 1} = a c, c^{z - 1} = a b

a^{x - 1} = b c, b^{y - 1} = a c, c^{z - 1} = a b

x y + y z + z x - x y z = 0

x = 1 + {log}_{a} b c, y = 1 + {log}_{b} c a, z = 1 + {log}_{c} a b

x y + y z + z x = x y z

(x y)^{a - 1} = z

(y z)^{b - 1} = x

(z x)^{c - 1} = y

a b + b c + c a = ?

If $a^{x - 1} = b c, b^{y - 1} = a c, c^{z - 1} = a b$ such that $x, y, z$ are integers then value of $x y + y z + z x - x y z$ is

Join BYJU'S Learning Program

Select...