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Question

If A={x:xR,0<x<2}, B={x:xR,1<x3}, then AB=

A
(0,1)
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B
(0,2)
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C
(1,3]
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D
(0,1]
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Solution

The correct option is D (0,1]
A={x:xR,0<x<2},
B={x:xR,1<x3}
AB={x:xR,1<x<2}
AB=A(AB)={x:xR,0<x1}=(0,1]

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