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Question

The elements of the set A={x:xZ, 32<x<112} are ______ (Here, Z stands for the set of integers).


A
-3, -2, -1, 0, 1, 2, 3, 4, 5
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B
-1, 0, 1, 2, 3, 4, 5, 6
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C
-1, 0, 1, 2, 3, 4, 5
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D
-2, -1, 0, 1, 2, 3, 4, 5
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Solution

The correct option is C -1, 0, 1, 2, 3, 4, 5

Given that A={x:xZ, 32<x<112}, where Z stands for the set of integers.

Since 32=1.5 and 112=5.5, the integers lying between -1.5 and 5.5 are -1, 0, 1, 2, 3, 4, and 5.
Thus, the elements of set A are -1, 0, 1, 2, 3, 4, and 5.


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