If AB is the-object and CD is the-image formed- If AP is the object distance and CP is the image distance from the mirror- Then choose the correct sign convention- - 1- height- of- image - - ve amp- 2- height- of- image - - ve- 3- height- of- object - - ve amp- 4- height- of- object - - ve- 5-AP - - ve amp- 6- AP - - ve- 7-PC - - ve amp- 7- PC - - ve- -concave mirror - 1- 3- 5 amp- 7- plane mirror - 1- 3- 5- 7 - - - -concave mirror - 2- 3- 6 amp- 8- plane mirror - 1- 3 - 6 - 7-concave mirror - 2- 3- 6 amp- 8- plane mirror - 1- 3- 6- 8-concave mirror - 2- 3- 5- 7- plane mirror - 1- 3- 6-

The correct option is B concave mirror – 2, 3, 6 amp; 8, plane mirror – 1, 3 , 6 , 7 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Sign Convention for Ray Diagram

If AB is the ...

Question

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 7. P C = + v e \end{matrix}$

concave mirror – 1, 3, 5 & 7, plane mirror – 1, 3, 5, 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3, 6, 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

concave mirror – 2, 3, 5, 7, plane mirror – 1, 3, 6,

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

Suggest Corrections

Similar questions

If AB is an object, CD is an image formed. If AP is object distance CP is image distance from the mirror. Then choose the correct sign convention.

1. height of image = + ve 2. height of image = – ve

3. height of object = + ve 4. height of object = – ve

5. AP = + ve 6. AP = – ve

7. PC = + ve 8. PC = – ve.

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. & h e i g h t o f i m a g e = + v e & 2. & h e i g h t o f i m a g e = - v e 3. & h e i g h t o f o b j e c t = + v e & 4. & h e i g h t o f o b j e c t = - v e 5. & A P = + v e & 6. & A P = - v e 7. & P C = + v e & 8. & P C = - v e \end{matrix}$

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 8. P C = - v e \end{matrix}$

AB refers to an object and CD is its image formed. If AP and CP are the object and image distances from the mirror, choose the correct sign convention:
$\begin{matrix} 1. height of image = + ve & 2. height of image = - ve 3. height of object = + ve & 4. height of object = - ve 5. AP = + ve & 6. AP = - ve 7. PC = + ve & 7. PC = + ve \end{matrix}$

Q. If AB is the object and CD is the image formed. If AP is the object distance and PC is the image distance from the mirror. Then choose the correct sign convention?
Assume that the object is beyond the focus in the case of concave mirror and new cartesian sign convention.

1. CD: Positive
2. CD: Negative
3. AB: Positive
4. AB: Negative
5. AP: Positive
6. AP: Negative
7. CP: Positive
8. CP: Negative

Join BYJU'S Learning Program

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention? 1. height of image=+ ve2. height of image=−ve3. height of object=+ve4. height of object=−ve5. AP=+ve6. AP=−ve7. PC=+ve7. PC=+ve

The correct option is B concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

The correct option is B
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7