Question

If $\alpha$ and $\beta$ are the roots of the equation $3x^2+x-10=0,$ then the value of $\frac{1}{\alpha }+\frac{1}{\beta }$ is......

• A. $10$
• B. $-\frac{1}{10}$
• C. $\frac{1}{10}$
• D. $\frac{1}{3}$

Answer 1

The correct option is C $\frac{1}{10}$

$\left(\frac{1}{\alpha }\right)+\left(\frac{1}{\beta }\right)=\left(\frac{\beta +\alpha }{\alpha \beta }\right)asweknow\alpha \beta =\left(\frac{c}{a}\right)=\left(\frac{-10}{3}\right)\therefore value=\left(\frac{\left(\frac{-1}{3}\right)}{\left(\frac{-10}{3}\right)}\right)=\left(\frac{1}{10}\right)$