We have to find
(1α+1β)
Now (1α+1β)=α+βαβ (taking LCM)
Now by the given polynomial.
f(x)=5x2−7x+1
we get,
(α+β)=−ba=75
αβ=ca=15
so,α+βαβ=(75)(15)
=71=7
If α and β are the zeros of the polynomial f(x)=5x2−7x+1, find the value of (1α+1β)..
If α&β are zeros of the polynomial f(x)=x2+px+q,then find a polynomial having 1/α & 1/β as its zeros.