Question

# If $$\alpha$$ and $$\beta$$ are zeros of quadratic equation $$f(x)=x^2-px+q$$, then find the values of the following:$$\alpha^2 +\beta^2$$

Solution

## Given $$\alpha$$ and $$\beta$$ are zeros quadratic equation $$f(x)=x^2-px+q$$$$\therefore \alpha +\beta =-\left( \dfrac {-p}{1}\right)=p$$and $$\alpha =\dfrac q1=q$$$$\alpha^2+\beta^2=(\alpha +\beta )^2-2\alpha \beta$$$$=p^2-2q$$Mathematics

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