Question

If $\alpha ,\beta$ are the zeros of the polynomial $x^2+6x+2$ then $(\frac{1}{\alpha }+\frac{1}{\beta })$ = ?

(a) 3 (b) -3 (c) 12 (d) -12

Answer 1

If α,β are the zeros of the polynomial x^2+6x+2

α+β=-b/a=-6/1=-6

αβ=c/a=2/1=2

then
(1/α+1/β)=(α+β)/αβ
=-6/2=-3

(b) -3 is correct option