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Question

If α is a reapeated root of ax2+bx+c=0, then limxatan(ax2+bx+c)(xα)2 is


A

a

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B

b

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C

c

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D

0

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Solution

The correct option is A

a


limxa[tan(ax2+bx+c)(xα)2]
=limxa[tan{a(xa)(xa)}a(xα)2]
=1×a
=a


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