If an arithmetic sequence has a common difference 10 and its $6^{t h}$ term is 52, then find its $15^{t h}$ term.

140

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142

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141

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132

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Solution

The correct option is B
142

In the AP; $T_{6}$ = 52 & d = 10 & n = 6

So, 52 = a + (6 – 1 )10
52 = a + 50
a = 2

As per question,

$T_{15}$ = 2 + (15 - 1)10
$T_{15}$ = 2 + 140
$T_{15}$ = 142.

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