If an electron has, orbital angular momentum quantum number l=7, then it will have an orbital angular momentum equal to
A
7(h2π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
42(h2π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2√14(h2π)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
√56(h2π)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A2√14(h2π) Given- * oribital angular momentum number ℓ=7 we know that - orbital angular momentum =√ℓ(ℓ+1)⋅(h2π) which is equal to =2√14⋅(h2π) for l=7