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Question

If an object accelerates from rest to velocity 30 m/s in 10 s, then the distance covered by the object during the next 10 s is

A
450 m
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B
300 m
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C
150 m
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D
600 m
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Solution

The correct option is A 450 m For the first 10 s: Initial velocity, u = 0 (As the object starts from rest) Final velocity, v = 30 m/s Time, t = 10 s Using first equation of motion, v = u + at Acceleration, a=v−ut=30−010 ⇒a=3m/s2 For the next 10 s: Initial velocity, u = 30 m/s Time, t = 10 s Acceleration, a=3m/s2 Using second equation of motion, s=ut+12at2 ⇒s=30×10+12×3×(10)2 ⇒s=300+150 ⇒s=450m Hence, the correct answer is option (a).

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