If an object is thrown at an angle of 60o with horizontal, find elevation angle of the object at its highest point as seen from the point of projection.
A
tan−1√32
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B
tan−112
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C
tan−11√2
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D
None of the above
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Solution
The correct option is Atan−1√32 The maximum height upto which the object goes, H=u2y2g=u2sin2θ2g