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Question
If area of a || gm with sides a and b is A and that of a rectangle with sides a and b is B, then
(a) A > B
(b) A = B
(c) A < B
(d) A ≥ B
(a) A > B
(b) A = B
(c) A < B
(d) A ≥ B
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Solution
(c) A < B
Explanation:
Let h be the height of parallelogram.
Then clearly, h < b
∴ A = a ⨯ h < a ⨯ b = B
Hence, A < B
Explanation:
Let h be the height of parallelogram.
Then clearly, h < b
∴ A = a ⨯ h < a ⨯ b = B
Hence, A < B
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