If area of triangle ABC is 16 then what will be area of triangle DEF where AF, BE and CD are medians of triangle ABC ?
The correct option is C 4 Now if we draw the segment AF, the triangle gets divided into two halves of equal area. ∴ Area(ΔAFC=8) Now EF becomes a median in the triangle AFC, dividing that triangle into two halves of equal area. ⟹ Area(ΔEFC)=4.
Using this logic we can also come to: Area(ΔDBF)=4 Area(ΔADE)=4