Question

# If at some point, the amplitude of a sound wave becomes double and the frequency becomes one fourth, then at that point, the intensity of sound will:

A
Become double
B
Become half
C
Become one fourth
D
Remain unchnaged

Solution

## The correct option is C Become one fourth I=2π2f2S20ρv where f= frequency S0= amplitude  Hence I∝f2S20 I1=kf21(S0)21→(1) Given, (S0)2=2(S0)1→(2) & f2=f14→(3) ⇒I2=kf22(S0)22→(4) Taking ratio of (1) & (2), I1I2=(f1f2)2((S0)1(S0)2)2 =(4)2(12)2=164=4 ∴I2=I14Physics

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