If- a-2- b-2 amp- b- a amp- 3 - - -x amp- 5- 2 amp- 3 - the value of x is-

([ a^2 b^2 amp; b; a amp; 3 ]) = ([ x amp; 5; 2 amp; 3 ]) Comparing the two matrices, we get a = 2 and b = 5 Therefore –x = a2 b2 ...

If ([ a^2- b^...

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If $(\begin{matrix} a^{2} - b^{2} & b a & 3 \end{matrix})$ = $(\begin{matrix} - x & 5 2 & 3 \end{matrix})$ , the value of x is ___.

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(\begin{matrix} a^{2} - b^{2} & b a & 3 \end{matrix})

(\begin{matrix} - x & 5 2 & 3 \end{matrix})

[2]

In a much-simplified form, the given algebraic expression could be written as: $(a^{2} + a b + b^{2}) (a - b)$

x = a + b, y = α x + b β

z = a β + b α,

α

β

x y z =

a^{2} + \frac{1}{a^{2}} = 34

a^{3} + \frac{1}{a^{3}}

(a^{2} + \frac{1}{a^{2}}) = 14

(i i) (a^{3} + \frac{1}{a^{3}})