Question

If Bohr radius is $r_0,$ the corresponding de Broglie wavelength of the electron is

• A. $\left(\frac{2\pi }{r_o}\right)$
• B. $\left(\frac{r_o}{2\pi }\right)$
• C. $\left(\frac{1}{2\pi r_o}\right)$
• D. $2\pi r_o$

Answer 1

The correct option is D $2\pi r_o$

Given that,

Radius $r=r_0$

We know that,

$2\pi r=n\lambda$

Suppose $n=1$

Then,

$\lambda =2\pi r_0$

Hence, this is the required solution