If $\frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}$ is the AM (arithmetic mean) between ' $a$ ' and ' $b$ ', then find the value of $n$ .

1

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0

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Solution

The correct option is D $0$
AM of $a$ and $b$ is $\frac{a + b}{2} = \frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}$
which is at $n = 0$

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Similar questions

a

b

\frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}

n

\frac{a^{n} + b^{n}}{a^{n - 1} + b^{n - 1}}

\frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}

The arithmetic mean of a and b is $\frac{a^{n} + b^{n}}{a^{n - 1} + b^{n - 1}}$ . The value of n is

\frac{a^{n} + b^{n}}{a^{n - 1} + b^{n - 1}}

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