If x-cx-1 - c- 1- find x-

The correct option is A 1c We use componendo dividendo to solve this, so, x+c x+1 =c+1 ⇒ x+c+x+1 x+c x 1 = c+1+1 c+1 1 ⇒ 2x+c+1 c 1 = ...

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General Solution of a Differential Equation

If x+cx+1 =...

Question

If $\frac{x + c}{x + 1} = c + 1$ , find $x$ .

\frac{- 1}{c}

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c - 2

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\frac{c - 1}{c}

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\frac{c - 1}{c + 1}

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Solution

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Similar questions

{(1 + x)}^{n} = C_{0} + C_{1} x + C_{2} x^{2} + . . . . . . . . . . + C_{n} x^{R}

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{(1 + x)}^{n} = C_{0} + C_{1} x + C_{2} x^{2} + . . . . + C_{n} x^{n}

\frac{1}{2} C_{1} + \frac{1}{4} C_{3} + \frac{1}{6} C_{5} + . . . .

{(1 + x)}^{n} = C_{0} + C_{1} x + C_{2} x^{2} + . . . + C_{n} x^{n}

C_{0} - C_{1} + C_{2} - C_{3} + . . . + {(- 1)}^{n} C_{n}

{(1 + x^{2})}^{2} {(1 + x)}^{n} = C_{0} + C_{1} x + C_{2} x^{2} + \cdot \cdot \cdot,

C_{0}, C_{1}, C_{2}

n

\frac{x + c}{x + 1} = c + 1

x

c

c \neq 0

c \neq - 1

x \neq - 1

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