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Question

If chord $$AOB $$ is diameter of the circle and $$AC = BC$$, then $$\angle$$ $$ACB$$ is equal to:

77945_4389b8e63d5d411cb513445b934cdcba.png


A
30
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B
60
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C
90
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D
45
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Solution

The correct option is B $$90$$
$$\angle ACB = 90^o$$ as it is inscribed in a semi circle.
So option C is the correct answer.

Mathematics

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