Question

# If chord $$AOB$$ is diameter of the circle and $$AC = BC$$, then $$\angle$$ $$ACB$$ is equal to:

A
30
B
60
C
90
D
45

Solution

## The correct option is B $$90$$$$\angle ACB = 90^o$$ as it is inscribed in a semi circle.So option C is the correct answer.Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More