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Question

If complex number 1+2i+3i212i+3i2 can be written in the form of a+ib, then ab= 


Solution

Let z=1+2i+3i212i+3i2
z=1+2i312i3
z=2i22i2z=1i1+i
z=1i1+i×1i1iz=1+i22i1i2
z=i
a=0,b=1
ab=0

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