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Question

If compressibility of material is 4×105 per atm, pressure is 100 atm and volume 100cm3 find a ΔV= ?

A
0.2cm3
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B
0.8cm3
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C
0.4cm3
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D
0.6cm3
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Solution

The correct option is C 0.4cm3
Given, compressibility of material =4×105per atm volume (v)=100 cm3=104 m3Δv=?
we know, Bulk modulus (B) =1 compressibility =14×105β=0.25×105 atm β=1.013×105 N/m2β=2.533×109 N/m2
and β=PvΔvΔv=PvβΔv=1.013×107×1042.533×109Δv=0.4×106 m3Δv=0.4 cm3

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