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Question

If cos1x+cos1y+cos1z=3π, then xy+yz+zx=
 
  1. 1
  2. -3
  3. 3
  4. 0


Solution

The correct option is C 3
Given cos1x+cos1y+cos1z=3π
0cos1xπ
0cos1yπ and 0cos1zπ
Here cos1x=cos1y=cos1z=π
x=y=z=cosπ=1
xy+yz+zx=(1)(1)+(1)(1)+(1)(1)
=1+1+1=3.

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