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if-cos-theta-isin-theta-cos2-theta-isin2-theta-cosn-theta-isinn-theta-1-then



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Q1.

If (cosθ+isinθ)(cos2θ+isin2θ)

(cosnθ+isinnθ)=1, then the value of θ is


Q2.

Express
 
(cos2θ+isin2θ)5 (cos3θisin3θ)6 (sinθicosθ)3
 in the form of A+iB is 


  1. (cos25 + isin25)

  2. i(cos25 + isin25)

  3. i(cos25 - isin25)

  4. (cos25 - isin25)

Q3.

If A=(cosθisinθisinθcosθ), where i=1, then by principle of Mathematical Induction then An=[cosnθisinnθisinnθcosnθ].


  1. True
  2. False
Q4.
Find the value of (cosθ+isinθ)n where θϵR,nϵI,i=1
Q5.

(cosθ+isinθsinθ+icosθ)4 equals


  1. sin8θ - icos8θ

  2. cos8θ + isin8θ

  3. sin8θ + icos8θ

  4. cos8θ + isin8θ


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