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Question 11
If ΔABCΔQRP,ar(ΔABC)ar(ΔPQR)=94, AB = 18 cm and BC = 15cm, then PR is equal to

(A) 10 cm
(B) 12 cm
(C)  203 cm
(D)​​​​​​​ 8cm


Solution

(A) 10 cm

Given, in ΔABCΔQRP,AB=18cm and BC=15cm


We know  that, the ratio of area of two similar triangles is equal to the ratio of square of their corresponding sides.
 ar(ΔABC)ar(ΔQRP)=(BC)2(RP)2
But given, ar(ΔABC)ar(ΔPQR)=94    [given]
 (15)2(RP)2=94  [ BC=15cm, given]
 (RP)2=225×49=100
 RP=10cm

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