The correct option is D 23
Given, |z−2||z−3|=2
⇒|z−2|=2|z−3|
⇒√(x−2)2+y2=2√(x−3)2+y2
⇒(x−2)2+y2=4[(x−3)2+y2] .....(on squaring both sides)
⇒x2+y2−4x+4=4x2+4y2+36−24x
⇒3x2+3y2−20x+32=0
or x2+y2−203x+323=0 ....(i)
We know that, standard equation of a circle is
x2+y2+2gx+2fy+c=0 ...(ii)
On comparing equations (i) and (ii), we get
2g=−203⇒g=−103,f=0,c=323
Hence, radius =√g2+f2−c
=√1009−323=√49=23