If lnx-1 2lnx-3lnx-2 - 2lnx-3 - lnx-2then -2-2-

(lnx+1) (2lnx 3)(lnx 2) =α nbsp; 2lnx 3 +β nbsp; lnx 2 ⇒ (lnx+1)=α (lnx 2)+β (2lnx 3) For x= e ^ 2 we get β =3 And for x= e ^ 3 ...

If lnx+1 2l...

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If $\frac{(l n x + 1)}{(2 l n x - 3) (l n x - 2)} = \frac{α}{2 l n x - 3} + \frac{β}{l n x - 2}$ then $α^{2} - β^{2} =$ ...

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