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Question

If sin(α+β)sin(αβ)=a+bab, where αβ, ab,b0, then tanαtanβ is

A
ab
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B
ba
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C
a2b
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D
ab
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Solution

The correct option is A ab
sin(α+β)sin(αβ)=a+babsinαcosβ+sinβcosαsinαcosβsinβcosα=a+bab

Using componendo and divinendo,
sinαcosβsinβcosα=abtanαtanβ=ab

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