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Question

If xy+yx=1 the value of x3y3 is

A
1
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B
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C
0
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D
12
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Solution

The correct option is C 0
xy+yx=1x2+y2xy=1

x2+y2=xy

Now, x3y3=(xy)(x2+y2+xy)

=(xy)(xy+xy) [x2+y2=xy]

=(xy)(0)

=0xy+yx=1x2+y2xy=1

x2+y2=xy

Now, x3y3=(xy)(x2+y2+xy)

=(xy)(xy+xy) [x2+y2=xy]

=(xy)(0)

=0

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