Question

If difference of reciprocal of roots of a quadratic equation $a{x}^2+bx+c=0$ is $\frac{1}{4}$, and difference of roots is 2. Then the value of c in the given equation is

• A. 8
• B. 6
• C. 3
• D. 4

Answer 1

The correct option is A

8

|$\frac{1}{x}-\frac{1}{y}$| = 1/4

and |x - y| = 2

Solving, we get, |xy| = 8.