If A={x:f(x)=0} and B={x:g(x)=0} then A∩B will be
Let , f(x)=ax2+bx+c, g(x)=ax2+px+q where a,b,c,q,p, ϵ R and b ≠ p. If their discriminants are equal and f(x) = g(x) has a root , α then
Let g(x)=∫x0f(t)dt and f(x) satisfies the equation f(x+y)=f(x)+f(y)+2xy−1 for all x, yϵR and f′(0)=2 then