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Question

If A=π(R2r2), then R is equal to

A
Aπr2π
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B
A+πr2π
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C
r2πAπ
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D
r2πAr
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Solution

The correct option is B A+πr2π
Given, A=π(R2r2)
Therefore, A= πR2πr2
A+πr2=πR2
R2=A+πr2π
R=A+πr2π

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