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Question

If α,β are the roots of the quadratic equation 4x216x+k=0,kR such that 1<α<2 and 2<β<3, then the number of integral values of k is

A
5
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B
6
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C
3
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D
2
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Solution

The correct option is C 3
Given,
f(x)=4x216x+k=0,kR
and 1<α<2 and 2<β<3
As a=4>0,
(i) f(1)>0
416+k>0
k>12
(ii) f(3)>0
3648+k>0
k>12
(iii) Discriminant, D>0
25616k>0
k<16
(iv) f(2)<0
1632+k<0
k<16
The integral value of k=13,14,15.
The no. of integral values are 3.
The correct answer is option C.

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