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Question

If cosA=3/4, then find the value of 32sin(A2)sin(5A2)

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Solution

The value of 32sin(A2)sin(5A2)
=16(cos2Acos3A)=16(2cos2A14cos3A+3cosA)
=16(2×91614×2764+3×34)
=1816+27+36=11

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