Question

If $\frac{\log 128}{\log 32}=\frac{m}{10}$, then value of $m$ is equal to

• A. $10$
• B. $16$
• C. $18$
• D. $14$

Answer 1

Answer: (D)

$14$

$\frac{\log 128}{\log 32}=\frac{\log 2^7}{\log 2^5}=\frac{7\log 2}{5\log 2}=\frac{7}{5}=\frac{14}{10}$