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Question

If b0dx1+x2=bdx1+x2, then b=

A
tan1(13)
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B
32
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C
3
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D
1
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Solution

The correct option is D 1
b0dx1+x2=bdx1+x2
[tan1x]b0=[tan1x]b
tan1b0=π2tan1b
tan1b=π4
b=tanπ4=1

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