If limx→0xasinbxsinxc where a,b,cϵR−{0},exists and has non-zero value. Then
A
a+c=b
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B
a+b=c
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C
a=b+c
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D
a+b+c=0
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Solution
The correct option is Da+b=c Since, this limit has to exist and be finite, we multiply and divide my the corresponding exponents of x. The question transforms to, limx→0xaxa×sinbxxb×xcsincx×xa+b−c For the limit to exist, a+b−c=0 Or, a+b=c