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Question

If tn=14(n+2)(n+3) for n=1,2,3,... then 1t1+1t2+1t3+...1t2003=

A
40063006
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B
40033007
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C
40063008
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D
40063009
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Solution

The correct option is A 40063006

tn=14(n+2)(n+3)

n=2003n=11tn=1t1+1t2++1t2003

n=2003n=14(n+2)(n+3)

=42003n=1(1n+21n+3)

=4(1312006)=40063009


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