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Question

If x2+y2=t1t and x4+y4=t2+1t2, then x3ydydx=

A
0
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B
1
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C
1
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D
none of these
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Solution

The correct option is A 1
We have x2+y2=t1t ..........(1)
x4+y4=t2+1t2 ................(2)
On squaring equation (1), we get
(x2+y2)2=t2+1t22
x4+2x2y2+y4=x4+y42 ..............from (2)
2x2y2=2
x2y2=1
y2=1x2
Differentiating both the sides,
2ydydx=2x3
x3ydydx=1

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