CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x2+y2=t−1t and x4+y4=t2+1t2, then x3ydydx=

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1
We have x2+y2=t1t ..........(1)
x4+y4=t2+1t2 ................(2)
On squaring equation (1), we get
(x2+y2)2=t2+1t22
x4+2x2y2+y4=x4+y42 ..............from (2)
2x2y2=2
x2y2=1
y2=1x2
Differentiating both the sides,
2ydydx=2x3
x3ydydx=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphical Method of Solving LPP
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon