CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If xdydx=y(logylogx+1), then the solution of the equation is

A
xlog(yx)=cy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
ylog(xy)=cx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
log(xy)=cy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
log(yx)=cx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C log(yx)=cx
xdydx=y(logylogx+1)
dydx=yx(log(yx)+1)
Now substitute yx=v
vlogvdx=xdy dyvlogv=dxx log(yx)=cx

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon