Question

If $E$ and $F$ be mutually exclusive events such that $P\left(E\right)=0.4$ and $P\left(F\right)=0.5$, then $P(E\cup F)$ is

• A. $0.2$
• B. $0.1$
• C. $0.9$
• D. None

Answer 1

Answer: (C)

$0.9$

Here, $E$ and $F$ be mutually exclusive events.

$\therefore$ P$(E\cap F)=0$

$\therefore$ P$(E\cup F)=$ P$\left(E\right)+$ P$\left(F\right)$

Given $P\left(E\right)=0.4$ and $P\left(F\right)=0.5$

$\therefore$ P$(E\cup F)=$ $0.4+0.5$

$\therefore$ $P$ $(E\cup F)=$ $0.9$

$\therefore$ option C is correct.