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Question

If f: [1,)[2,) is given by f(x)=x+1x  , then f1(x) is equal to
  1. x+x242
  2. x1+x2
  3. xx242
  4. 1+x4


Solution

The correct option is A x+x242
f(x)=x+1x, for f1(x) Put f (x) = y
y=x2+1x or x2 - xy + 1 = 0
x=y±y242
f1(y)=y+y242     (neglect - ve, as x > 1)
f1(x)=x+x242

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