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Question

If f:RR,f(x)=(x+1)2 and g:RR,g(x)=x2+1 then (fog)(3) is equal to

A
121
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B
144
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C
112
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D
11
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Solution

The correct option is A 121
Given,
f:RR,f(x)=(x+1)2 and g:RR,g(x)=x2+1
g(3)=32+1=10
f(10)=(10+1)2=121
fog(3)=f(g(3))=f(10)=121
Hence, option A.

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